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Formula:1115

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Digital Library of Mathematical Functions ID 3.3#Ex20

A 1 5 = 1 12 ⁢ t ⁢ ( t + 1 ) ⁢ ( t 2 - 4 ) ⁢ ( t - 3 ) , superscript subscript 𝐴 1 5 1 12 𝑡 𝑡 1 superscript 𝑡 2 4 𝑡 3 {\displaystyle{\displaystyle A_{1}^{5}=\tfrac{1}{12}t(t+1)(t^{2}-4)(t-3),}}


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