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Formula:1180

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Digital Library of Mathematical Functions ID 3.4#Ex20

B 1 6 = 1 48 ⁢ ( 36 + 72 ⁢ t - 39 ⁢ t 2 - 52 ⁢ t 3 + 5 ⁢ t 4 + 6 ⁢ t 5 ) , superscript subscript 𝐵 1 6 1 48 36 72 𝑡 39 superscript 𝑡 2 52 superscript 𝑡 3 5 superscript 𝑡 4 6 superscript 𝑡 5 {\displaystyle{\displaystyle B_{1}^{6}=\tfrac{1}{48}(36+72t-39t^{2}-52t^{3}+5t% ^{4}+6t^{5}),}}


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