Formula:1315

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Digital Library of Mathematical Functions ID 3.7.E10

๐€ = [ - ๐€ โข ( ฯ„ 0 , z 0 ) ๐ˆ ๐ŸŽ โ‹ฏ ๐ŸŽ ๐ŸŽ ๐ŸŽ - ๐€ โข ( ฯ„ 1 , z 1 ) ๐ˆ โ‹ฏ ๐ŸŽ ๐ŸŽ โ‹ฎ โ‹ฎ โ‹ฑ โ‹ฑ โ‹ฎ โ‹ฎ ๐ŸŽ ๐ŸŽ โ‹ฏ - ๐€ โข ( ฯ„ P - 2 , z P - 2 ) ๐ˆ ๐ŸŽ ๐ŸŽ ๐ŸŽ โ‹ฏ ๐ŸŽ - ๐€ โข ( ฯ„ P - 1 , z P - 1 ) ๐ˆ ] ๐€ ๐€ subscript ๐œ 0 subscript ๐‘ง 0 ๐ˆ 0 โ‹ฏ 0 0 0 ๐€ subscript ๐œ 1 subscript ๐‘ง 1 ๐ˆ โ‹ฏ 0 0 โ‹ฎ โ‹ฎ โ‹ฑ โ‹ฑ โ‹ฎ โ‹ฎ 0 0 โ‹ฏ ๐€ subscript ๐œ ๐‘ƒ 2 subscript ๐‘ง ๐‘ƒ 2 ๐ˆ 0 0 0 โ‹ฏ 0 ๐€ subscript ๐œ ๐‘ƒ 1 subscript ๐‘ง ๐‘ƒ 1 ๐ˆ {\displaystyle{\displaystyle\mathbf{A}=\begin{bmatrix}-\mathbf{A}(\tau_{0},z_{% 0})&\mathbf{I}&\boldsymbol{{0}}&\cdots&\boldsymbol{{0}}&\boldsymbol{{0}}\\ \boldsymbol{{0}}&-\mathbf{A}(\tau_{1},z_{1})&\mathbf{I}&\cdots&\boldsymbol{{0}% }&\boldsymbol{{0}}\\ \vdots&\vdots&\ddots&\ddots&\vdots&\vdots\\ \boldsymbol{{0}}&\boldsymbol{{0}}&\cdots&-\mathbf{A}(\tau_{P-2},z_{P-2})&% \mathbf{I}&\boldsymbol{{0}}\\ \boldsymbol{{0}}&\boldsymbol{{0}}&\cdots&\boldsymbol{{0}}&-\mathbf{A}(\tau_{P-% 1},z_{P-1})&\mathbf{I}\end{bmatrix}}}


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