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Formula:144

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Digital Library of Mathematical Functions ID 1.6.E2

𝐚 β‹… 𝐛 = a 1 ⁒ b 1 + a 2 ⁒ b 2 + a 3 ⁒ b 3 . β‹… 𝐚 𝐛 subscript π‘Ž 1 subscript 𝑏 1 subscript π‘Ž 2 subscript 𝑏 2 subscript π‘Ž 3 subscript 𝑏 3 {\displaystyle{\displaystyle\mathbf{a}\cdot\mathbf{b}=a_{1}b_{1}+a_{2}b_{2}+a_% {3}b_{3}.}}


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