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Formula:373

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Digital Library of Mathematical Functions ID 1.11#Ex10

ρ = - 1 2 + 1 2 ⁢ - 3 = e 2 ⁢ π ⁢ i / 3 , 𝜌 1 2 1 2 3 superscript 𝑒 2 𝜋 𝑖 3 {\displaystyle{\displaystyle\rho=-\tfrac{1}{2}+\tfrac{1}{2}\sqrt{-3}=e^{2\pi i% /3},}}


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