Formula:3916

Digital Library of Mathematical Functions ID 10.19#Ex2

${\displaystyle{\displaystyle Y_{\nu}\left(\nu\operatorname{sech}\alpha\right)\sim-\frac{e^{\nu(\alpha-\tanh\alpha)}}{(\tfrac{1}{2}\pi\nu\tanh\alpha)^{\frac{1}{2}}}\*\sum_{k=0}^{\infty}(-1)^{k}\frac{U_{k}(\coth\alpha)}{\nu^{k}},}}$

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