Formula:8153

Digital Library of Mathematical Functions ID 24.5.E8

${\displaystyle{\displaystyle\sum_{k=0}^{n}\frac{2^{2k}B_{2k}}{(2k)!(2n+1-2k)!}=\frac{1}{(2n)!},}}$

Constraint(s)

${\displaystyle{\displaystyle n=1,2,\dots}}$

Symbols List

• ${\displaystyle{\displaystyle B_{\NVar{n}}}}$:
• ${\displaystyle{\displaystyle!}}$:
• ${\displaystyle{\displaystyle k}}$: integer
• ${\displaystyle{\displaystyle n}}$: integer
 

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