Formula:8262

Digital Library of Mathematical Functions ID 24.15.E12

${\displaystyle{\displaystyle\sum_{k=0}^{\left\lfloor\ifrac{n}{2}\right\rfloor}{n\choose 2k}\left(\frac{5}{4}\right)^{k}E_{2k}v_{n-2k}=\frac{1}{2^{n-1}}.}}$

Symbols List

• ${\displaystyle{\displaystyle E_{\NVar{n}}}}$:
• ${\displaystyle{\displaystyle\genfrac{(}{)}{0.0pt}{}{\NVar{m}}{\NVar{n}}}}$:
• ${\displaystyle{\displaystyle\left\lfloor\NVar{x}\right\rfloor}}$:
• ${\displaystyle{\displaystyle k}}$: integer
• ${\displaystyle{\displaystyle n}}$: integer
• ${\displaystyle{\displaystyle v_{n}}}$: Lucas numbers
 

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