Commensurability classes of \((- 2,3,n)\) pretzel knot complements (Q1007173)
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| Language | Label | Description | Also known as |
|---|---|---|---|
| English | Commensurability classes of \((- 2,3,n)\) pretzel knot complements |
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Commensurability classes of \((- 2,3,n)\) pretzel knot complements (English)
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20 March 2009
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Two hyperbolic 3-manifolds are commensurable if they have homeomorphic finite-sheeted covering spaces. It is known that if a hyperbolic knot \(K\) (1) admits no hidden symmetries, (2) has no lens space surgery and (3) admits either no symmetries or else only a strong inversion and no other symmetries, then \(S^3/K\) is the only knot complement in its commensurability class. For a \((-2, 3, n)\)-pretzel knot \(K\), it is known that \(K\) satisfies properties (2) and (3) with some integers \(n\) as an exception. In this paper the authors prove that a hyperbolic \((-2, 3, n)\)-pretzel knot \(K\) has property (1) by showing a sufficient condition that the trace field \(k\Gamma \) contains neither \(\mathbb{Q} (i)\) nor \(\mathbb{Q} (\sqrt{-3})\), where \(\Gamma \) is a torsion free subgroup of \(\text{PSL} _2\mathbb{C}\) with \(S^3/K \cong \mathbb{H}^3/\Gamma\) and \(k\Gamma = \mathbb{Q}(\{\text{tr}\gamma ^2 : \gamma \in \Gamma\} )\)
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commensurability class
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pretzel knot
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trace field
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