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Statements
6
j
j
1
j
2
j
3
1
j
3
j
2
=
(
-
1
)
J
+
1
2
(
j
2
(
j
2
+
1
)
+
j
3
(
j
3
+
1
)
-
j
1
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j
1
+
1
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)
(
2
j
2
(
2
j
2
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1
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(
2
j
2
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2
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2
j
3
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2
j
3
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1
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2
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2
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1
2
.
sixj
subscript
𝑗
1
subscript
𝑗
2
subscript
𝑗
3
1
subscript
𝑗
3
subscript
𝑗
2
superscript
1
𝐽
1
2
subscript
𝑗
2
subscript
𝑗
2
1
subscript
𝑗
3
subscript
𝑗
3
1
subscript
𝑗
1
subscript
𝑗
1
1
superscript
2
subscript
𝑗
2
2
subscript
𝑗
2
1
2
subscript
𝑗
2
2
2
subscript
𝑗
3
2
subscript
𝑗
3
1
2
subscript
𝑗
3
2
1
2
{\displaystyle{\displaystyle\mathit{6j}{j_{1}}{j_{2}}{j_{3}}{1}{j_{3}}{j_{2}}=%
(-1)^{J+1}\frac{2(j_{2}(j_{2}+1)+j_{3}(j_{3}+1)-j_{1}(j_{1}+1))}{\left(2j_{2}(%
2j_{2}+1)(2j_{2}+2)2j_{3}(2j_{3}+1)(2j_{3}+2)\right)^{\frac{1}{2}}}.}}
6
j
j
1
j
2
j
3
l
1
l
sixj
subscript
𝑗
1
subscript
𝑗
2
subscript
𝑗
3
subscript
𝑙
1
𝑙
{\displaystyle{\displaystyle\mathit{6j}{\NVar{j_{1}}}{\NVar{j_{2}}}{\NVar{j_{3%
}}}{\NVar{l_{1}}}{\NVar{l}\)\@add@PDF@RDFa@triples\end{document}}}}
j
,
j
r
𝑗
subscript
𝑗
𝑟
{\displaystyle{\displaystyle j,j_{r}}}
J
𝐽
{\displaystyle{\displaystyle J}}
Identifiers
