If \(f\) has Lipschitz constant less than 2.17008, then \(x_{i+1}=x_ i+f(x_ i)\) has no odd periodic solutions (Q1192544)
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scientific article; zbMATH DE number 60992
| Language | Label | Description | Also known as |
|---|---|---|---|
| English | If \(f\) has Lipschitz constant less than 2.17008, then \(x_{i+1}=x_ i+f(x_ i)\) has no odd periodic solutions |
scientific article; zbMATH DE number 60992 |
Statements
If \(f\) has Lipschitz constant less than 2.17008, then \(x_{i+1}=x_ i+f(x_ i)\) has no odd periodic solutions (English)
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27 September 1992
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recurrence relation
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periodic solutions
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Lipschitz continuous function
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Lipschitz constant
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0.79573226
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0.7903791
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0.78863734
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0.7876714
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0.78654027
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