Remarks on the Grunsky norm and \(p\)th root transformation (Q1301971)

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scientific article; zbMATH DE number 1334872
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Remarks on the Grunsky norm and \(p\)th root transformation
scientific article; zbMATH DE number 1334872

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    Remarks on the Grunsky norm and \(p\)th root transformation (English)
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    5 September 2000
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    Let \(S\) denote the class of functions \(f\) holomorphic and univalent in the unit disc \(E\), and normalized by the conditions \(f(0)= 0\), \(f'(0)=1\). Each function \(f\in S\) generates its Grunsky operator \(G_f= \{\sqrt{nm} \alpha_{n,m} \}_{n,m=1}^\infty: l^2\to l^2\), where \(\alpha_{n,m}\) are determined by the expansion \(\log [f(z)- f(\zeta)]/ (z-\zeta)= \sum_{n,m=0}^\infty \alpha_{n,m} z^n \zeta^m\), \(z,\zeta\in E\). Here \(l^2\) is the Hilbert space of all square-summable complex sequences \(X= (x_1, x_2,\dots)\), with the norm \(\|X\|= (\sum_{n=1}^\infty|x_n|^2)^{1/2}\). The author shows that the norm of the Grunsky operator generated by a univalent function does not decrease with the \(p\)th root transformation, i.e. there holds the theorem: Let \(f\in S\), \(p=2,3,\dots\), and let \(g\) be defined by the formula \(g(z)= \root p\of {f(z^p)}\), \(z\in E\). Then \(\|G_f\|\leq \|G_g\|\). This inequality is sharp for each \(p\) and over each subclass \(\{f\in S: \|G_f\|= k\}\), \(0\leq k\leq 1\).
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    univalent functions
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    Grunsky norm
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    \(p\)th root transformation
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