On iterated group actions and direct products (Q1969115)

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scientific article; zbMATH DE number 1415745
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On iterated group actions and direct products
scientific article; zbMATH DE number 1415745

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    On iterated group actions and direct products (English)
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    28 August 2000
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    Given a group \(G\), let it act on itself via conjugation. Consider the corresponding semidirect product \(G\propto G\). Then it is known that \(G\propto G\cong G\times G\) (this result has appeared as Exercise 7.10 in \textit{I. M. Isaacs'} ``Algebra; a graduate course'' (1993; Zbl 0805.00001)). In this paper the author expands this idea. Let \(G\) be a group and \(t\geq 2\) an integer. Consider the set \(G^t\), consisting of all \(t\)-tuples \((a,b,\ldots)\), where \(a,b,\ldots\in G\). We can equip \(G^t\) with an operation \(*\) by means of \[ (a,b,c,d,\ldots)*(\overline a,\overline b,\overline c,\overline d,\ldots)=(({^1 a})\overline a,({^{\overline a^{-1}} b})\overline b,({^{(\overline a\overline b)^{-1}} c})\overline c,({^{(\overline a\overline b\overline c)^{-1}} d})\overline d,\ldots), \] where \({^yx}=yxy^{-1}\). \(G^t\) has a group structure under the operation \(*\). Some properties of the group \(G^t\) are studied. These considerations give rise to the following theorem: Suppose that \(M\) and \(N\) are normal subgroups of \(G\). Let \(H=\{b\in G\mid\) there exists \(a\in M\) such that \(ab\in N\}\). Then \(H=MN\).
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    products of subgroups
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    semidirect products
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    normal subgroups
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