Is an interacting ground state (pure state) \(v\)-representable density also non-interacting ground state \(v\)-representable by a Slater determinant? In the absence of degeneracy, yes! (Q2231976)

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Is an interacting ground state (pure state) \(v\)-representable density also non-interacting ground state \(v\)-representable by a Slater determinant? In the absence of degeneracy, yes!
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    Is an interacting ground state (pure state) \(v\)-representable density also non-interacting ground state \(v\)-representable by a Slater determinant? In the absence of degeneracy, yes! (English)
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    30 September 2021
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    proof of Kohn-Sham conjecture
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    Kohn-Sham density functional theory
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    \(v\)-representability
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    pure state interacting \(v\)-representable
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    pure state non-interacting \(v\)-representable
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    derivation of Kohn-Sham potential
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