The bidual of a radical operator algebra can be semisimple (Q2346666)
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| Language | Label | Description | Also known as |
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| English | The bidual of a radical operator algebra can be semisimple |
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The bidual of a radical operator algebra can be semisimple (English)
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3 June 2015
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\textit{S. L. Gulick} claimed in [ibid. 18, 121--137 (1966; Zbl 0198.17901)] that the intersection of a Banach algebra \(A\) with the radical of its bidual \(A^{**}\) is the radical of \(A\). The author of the paper under review gives a simple counterexample to that claim. Further, the author looks at the papers which have referenced the above mentioned paper and he points out that he did not find a case in which Gulick's wrong result is used.
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radical Banach algebra
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bidual operator algebra
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0.8726978
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0.8611349
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