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The Hilbert transform does not map \(L^1(M\omega)\) to \(L^{1,\infty}(\omega)\) - MaRDI portal

The Hilbert transform does not map \(L^1(M\omega)\) to \(L^{1,\infty}(\omega)\) (Q2391580)

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The Hilbert transform does not map \(L^1(M\omega)\) to \(L^{1,\infty}(\omega)\)
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    The Hilbert transform does not map \(L^1(M\omega)\) to \(L^{1,\infty}(\omega)\) (English)
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    5 August 2013
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    Hilbert transform
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    Hardy-Littlewood maximal operator
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