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Rotationally symmetric symphonic maps - MaRDI portal

Rotationally symmetric symphonic maps (Q2673430)

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Rotationally symmetric symphonic maps
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    Rotationally symmetric symphonic maps (English)
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    9 June 2022
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    Let \(f:M\rightarrow N\) be a smooth map between two Riemannian manifolds without boundary \((M, g)\) and \((N, h)\), respectively. The the symphonic energy or symphonic functional of \(f\) is given by \(E_{\mathrm{sym}}(f)=\int_M||f^*h||^2dv_g\), where \(dv_g\) is the volume form on \((M, g)\) and \(||f^*h||\) denotes the norm of the pullback \(f^*h\). Stationary maps for the symphonic energy \(E_{\mathrm{sym}}(f)\) are called as symphonic maps. In this paper, the author considers rotationally symmetric maps \(f:M^n(\varphi)\rightarrow N^n(\psi)\), \(f(r,\omega)=(y(r),\omega)\), where \[ M^n(\varphi)=([0,\infty)\times S^{n-1},g_{[0,\infty)}+\varphi(r)^2g_{S^{n-1}}), \] \[ N^n(\psi)=([0,\infty)\times S^{n-1},g_{[0,\infty)}+\psi(r)^2g_{S^{n-1}}) \] and focusses on the case \(n=4\). It is proven that a rotationally symmetric map \(f:M^4(\varphi)\rightarrow N^4(\psi)\) satisfying \(y(0)=0\) is a symphonic map if and only if \(f\) is a conformal map.
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    variational problem
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    pullbacks of metrics
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    symphonic map
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    rotationally symmetric
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    conformal map
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    harmonic map
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