Topological spectrum and perfectoid Tate rings (Q2676962)
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| Language | Label | Description | Also known as |
|---|---|---|---|
| English | Topological spectrum and perfectoid Tate rings |
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Topological spectrum and perfectoid Tate rings (English)
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29 September 2022
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Let \(R\) be a seminormed ring and let \(J \subsetneq A\) be an ideal. Then \(J\) is called \textit{spectrally reduced} if there exists a power-multiplicative bounded seminorm \(\phi\) on \(A\) such that \(\text{ker }\phi = J\). Moreover, the \textit{topological spectrum} of \(A\) is the subspace \[ \mathrm{Spec}_{\mathrm{Top}}(A) = \{ \mathfrak{p} \in \mathrm{Spec}(A)~|~\mathfrak{p}\text{ is spectrally reduced}\}. \] of Spec(\(A\)) endowed with the subspace topology induced by the Zariski topology on Spec(\(A\)). The main result in this paper is the existence of the the homeomorphism between the topological spectrum of a perfectoid Tate ring \(A\) and that of its tilt \(A^\flat\). More precisely, he proved that there is a following homeomorphism for Zariski topology on \(\mathrm{Spec}_{\mathrm{Top}}(A)\) and \(\mathrm{Spec}_{\mathrm{Top}}(A^\flat)\) \[ \mathrm{Spec}_{\mathrm{Top}}(A) \to\mathrm{Spec}_{\mathrm{Top}}(A^\flat) ~;~ \mathfrak{p} \mapsto \mathfrak{p}^\flat = \{ (f^{(n)})_{n\geq 0}\in R^\flat~|~f^{(0)} \in \mathfrak{p} \}, \] and its inverse \(\mathfrak{q} \mapsto \mathfrak{q}^{\sharp}\) is formulated using the homeomorphism of the Berkovich spectrum of \(A\) and that of its tilt \(A^\flat\). As a corollary, the author showed a perfectoid Tate ring \(A\) is an integral domain if and only if its tilt \(A^\flat\) is also an integral domain.
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tilting equivalence
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perfectoid rings
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Banach rings
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Tate rings
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