How algebraic is algebra? (Q2710150)

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How algebraic is algebra?
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    18 April 2001
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    variety
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    exact category
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    pseudomonad
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    finitary varieties
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    equational hull
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    algebraically exact categories
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    sifted colimits
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    How algebraic is algebra? (English)
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    The inclusion functor of the 2-category \({\mathcal V}{\mathcal A}{\mathcal R}\) of all finitary varieties (with finitary right adjoint functors preserving regular epimorphisms as arrows, and with natural transformations as 2-cells) into the (larger) 2-category \({\mathcal C}{\mathcal A}{\mathcal T}\) of all categories fails to create split coequalizers and therefore fails to be (pseudo)monadic. Hence, the problem at hand is to determine the (reasonably defined) equational hull of \({\mathcal V}{\mathcal A}{\mathcal R}\) in \({\mathcal C}{\mathcal A}{\mathcal T}\).NEWLINENEWLINENEWLINEThe authors offer a solution under the restriction to ranked operations: it is the 2-category \({\mathcal A}{\mathcal L}{\mathcal G}\) of algebraically exact categories, i.e., of complete categories with sifted colimits which distribute over limits, with functors preserving limits and sifted colimits as arrows, and with all natural transformations. \({\mathcal A}{\mathcal L}{\mathcal G}\) is bi-equivalent to the 2-category of algebras of the composite pseudomonad \(Sind\circ Lim\), where \textit{Lim} is the free-completion 2-monad under limits and \textit{Sind} that one under sifted colimits; the pseudomonad exists since \textit{Sind} (Beck-)distributes over \textit{Lim}. The authors also mention a number of challenging open problems.
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