The Drazin inverse of matrices over rings (Q2735491)
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scientific article; zbMATH DE number 1640478
| Language | Label | Description | Also known as |
|---|---|---|---|
| English | The Drazin inverse of matrices over rings |
scientific article; zbMATH DE number 1640478 |
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24 November 2002
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generalized inverse
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commutative ring
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group inverse
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Drazin inverse
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The Drazin inverse of matrices over rings (English)
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Let \(A\) be a square matrix over a commutative ring and let \(k\) be the index of \(A\), so that \(A^k\), \(A^{k+1}\) have the same rank. Suppose there exist matrices \(B,P,Q,P',Q'\) such that \(A^k=PBQ\), \(P'PB=B=BQQ'\). Assume that \(B\) has a group inverse \(B^\#\) and let \(X=BB^\# QAPB+ I-BB^\#\), where \(I\) is the unit matrix. The authors prove that \(A\) has a Drazin inverse \(A^D\) if, and only if, \(X\) is invertible, \(A^D\) being \(PBX^{-1}Q\) when this condition holds. A somewhat similar result is proved in the case where the coefficient ring is non-commutative, conditions like above being imposed on every power of \(A\).
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