The Dunford-Pettis property on tensor products (Q2743684)
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scientific article; zbMATH DE number 1652433
| Language | Label | Description | Also known as |
|---|---|---|---|
| English | The Dunford-Pettis property on tensor products |
scientific article; zbMATH DE number 1652433 |
Statements
6 November 2001
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Schur property
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\(L_\infty\)-spaces
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\(C(K)\) spaces
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weakly compact operator
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completely continuous
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Dunford-Pettis property
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\(\varepsilon\)- or \(\pi\)-tensor product
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0.98234534
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0.9701494
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0.94589686
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0.94532585
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0.9442937
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0.9400965
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0.93955564
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The Dunford-Pettis property on tensor products (English)
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Recall that a Banach space \(E\) has the Dunford-Pettis property (DPP), if every weakly compact operator on \(E\) is completely continuous. Sometimes this property is transmitted to the \(\varepsilon\)- or \(\pi\)-tensor product, sometimes not. If \(E\) and \(F\) have the DPP and does not contain any copy of \(\ell^1\) then \(E\otimes_\pi F\) shares this property. On the other hand there are Banach spaces \(E\) with \(E, E^*\in\text{DPP}\), but \(C[0,1]\otimes_\varepsilon E\) and \(C[0,1]\otimes_\pi E^*\) fail the DPP. In the paper under review the authors found some general conditions under which \(E\otimes_\pi F\) and \(E\otimes_\varepsilon F\) or their duals do not have the DPP. In particular, \((c_0\otimes_\pi c_0)^{**}\) fails the DPP, but \((c_0\otimes_\pi c_0)\) has it.
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