Invariant sequences under binomial transformation (Q2746560)

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scientific article; zbMATH DE number 1656221
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Invariant sequences under binomial transformation
scientific article; zbMATH DE number 1656221

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    27 June 2002
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    inversion formula
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    inverse invariant sequence
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    Fibonacci, Lucas and Bernoulli numbers
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    generating function
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    Invariant sequences under binomial transformation (English)
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    The classical binomial inversion formula states that NEWLINE\[NEWLINE\alpha_n= \sum^n_{k=0} {n\choose k}(-1)^k b_k\qquad (n= 0,1,2,\dots)\qquad\text{if and only if}NEWLINE\]NEWLINE NEWLINE\[NEWLINEb_n= \sum^n_{k=0} {n\choose k}(-1)^k \alpha_k\qquad (n= 0,1,2,\dots).NEWLINE\]NEWLINE In the present paper the author studies those sequences \(\{\alpha_n\}\) which satisfy the relation NEWLINE\[NEWLINE\sum^n_{k=0} {n\choose k}(-1)^k \alpha_k= +\alpha_n\qquad (n= 0,1,2,\dots)NEWLINE\]NEWLINE and those which satisfy the relation NEWLINE\[NEWLINE\sum^n_{k=0} {n\choose k}(-1)^k \alpha_k= -\alpha_n\qquad (n= 0,1,2,\dots).NEWLINE\]NEWLINE A sequence, which satisfies the first relation, is called invariant sequence (IS), and a sequence, which satisfies the second, is called inverse invariant sequence (IIS). The author notes that \(\{\alpha_n\}\in \text{ISS}\) if and only if \(\alpha_0= 0\) and either \(\{\alpha_{n+1}/(n+ 1)\}\) or \(\{n\alpha_{n-1}\}\in \text{IS}\). He also notes that \(\{1/2^n\}\), \(\{[nF_{n-1}\}\), \(\{L_n\}\) and \(\{(-1)^n B_n\}\) are invariant sequences, where \(F_n\), \(L_n\), and \(B_n\) denote the Fibonacci, Lucas and Bernoulli numbers. Finally, he proves a number of results among which we mention the following. NEWLINENEWLINETheorem 3.2: Let \(A^*(x)\) be the exponential generating function of \(\{A_n\}\). Then \(\{A_n\}\in \text{IS}\) if and only if \(A^*(x) e^{-x/2}\) is an even function, and \(\{A_n\}\in \text{IIS}\) if and only if \(A^*(x) e^{-x/2}\) is an odd function. NEWLINENEWLINETheorem 5.1: Let \(\{a_n\}\), \(\{b_n\}\) and \(\{c_n\}\) be three nonzero sequences satisfying NEWLINE\[NEWLINEc_n= [1/(n+ 1)]= \sum^n_{k=0} a_k b_{n-k}\qquad (n= 0,1,2,\dots).NEWLINE\]NEWLINE If two of the three sequences are invariant sequences, then the other sequence is also an invariant sequence.
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