An example of a factor map without a saturated compensation function (Q2773062)

From MaRDI portal





scientific article; zbMATH DE number 1709206
Language Label Description Also known as
English
An example of a factor map without a saturated compensation function
scientific article; zbMATH DE number 1709206

    Statements

    0 references
    5 August 2002
    0 references
    symbolic dynamics
    0 references
    saturated compensation function
    0 references
    factor map
    0 references
    subshifts of finite type
    0 references
    non-Markovian factor map
    0 references
    An example of a factor map without a saturated compensation function (English)
    0 references
    Let \((X,S)\) and \((Y,T)\) be two topological dynamical systems. Let \(\pi:X\to Y\) be a factor map. A continued function \(F\) of \(X\) is a compensation function if for all continued function \(\varphi\) of \(Y\), we have \(P_X [F+\varphi\circ \pi]= P_Y(\varphi)\) where \(P\) is the pressure function. It is known that there always exists a compensation function when \(X\) and \(Y\) are irreducible subshifts of finite type. Moreover a compensation function is a saturated compensation function if there exists a continued function \(G\) of \(Y\) such that \(F= G\circ \pi\). NEWLINENEWLINENEWLINEIn this paper the author discusses the existence of saturated compensation function. In the first part of the paper, the author presents an example of a factor map between two subshifts of finite type that does not have a saturated compensation function. He also presents an example of a non-Markovian factor map with a saturated compensation function. NEWLINENEWLINENEWLINEIn the second part of the paper, the author gives a necessary and sufficient condition for a certain type of factor map to have a saturated compensation function.
    0 references

    Identifiers