An implicit degree Dirac condition for Hamiltonian cycles. (Q2864472)
From MaRDI portal
| This is the item page for this Wikibase entity, intended for internal use and editing purposes. Please use this page instead for the normal view: An implicit degree Dirac condition for Hamiltonian cycles. |
scientific article; zbMATH DE number 6236468
| Language | Label | Description | Also known as |
|---|---|---|---|
| English | An implicit degree Dirac condition for Hamiltonian cycles. |
scientific article; zbMATH DE number 6236468 |
Statements
6 December 2013
0 references
implicit degree
0 references
Hamiltonicity
0 references
independence number
0 references
0.89133906
0 references
0 references
0.87330735
0 references
0.86776173
0 references
0.8665091
0 references
0.86029357
0 references
An implicit degree Dirac condition for Hamiltonian cycles. (English)
0 references
In this paper the authors deal with a concept of an implicit degree of a vertex in a graph \(G\) defined by \textit{Y. Zhu} et al. in [Graphs Comb. 5, No. 3, 283--290 (1989; Zbl 0701.05030)]. The implicit degree of a vertex generalizes the classical degree of a vertex and it has the classical degree as a lower bound. Zhu et al. [loc. cit.] proved sufficient conditions for Hamiltonicity of \(G\) in terms of the implicit degree of every vertex of \(G\), namely that every \(2\)-connected graph \(G\) of order \(n\) with \(\mathrm{id}(v)\geq \frac n2\) for each \(v\in V(G)\) contains a Hamiltonian cycle. In this paper, the authors show that if \(G\) is a \(2\)-connected graph of order \(n\) with the independence number \(\alpha (G)\leq \frac n2\) and \(\mathrm{id}(v)\geq \frac {n-1}2\) for every \(v\in V(G)\), then \(G\) is Hamiltonian with some exceptions.
0 references