Truth definitions without exponentiation and the \(\Sigma _{1}\) collection scheme (Q2892683)
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scientific article; zbMATH DE number 6047782
| Language | Label | Description | Also known as |
|---|---|---|---|
| English | Truth definitions without exponentiation and the \(\Sigma _{1}\) collection scheme |
scientific article; zbMATH DE number 6047782 |
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19 June 2012
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collection principle
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exponentiation
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bounded arithmetic
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truth definitions
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Truth definitions without exponentiation and the \(\Sigma _{1}\) collection scheme (English)
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The paper presents three results related to the notoriously difficult open problem: Is the theory \(\mathrm{I}\Delta_0+\lnot \mathrm{exp}+\lnot \mathrm{B}\Sigma_1\) consistent? It is well known that if there is a model of \(\mathrm{I}\Delta_0+\lnot \mathrm{exp}\) with a universal \(\Sigma_1\) formula, then there is also a model of \(\mathrm{I}\Delta_0+\lnot \mathrm{exp}+\lnot \mathrm{B}\Sigma_1\). The first result weakens the assumption a bit. It is shown that if there is a model of \(\mathrm{I}\Delta_0+\lnot \mathrm{exp}\) with cofinal \(\Sigma_1\)-definable elements and a \(\Sigma_1\) truth definition for sentences, then \(\mathrm{I}\Delta_0+\lnot \mathrm{exp}+\lnot \mathrm{B}\Sigma_1\) is consistent. It is not know whether such models exist, but in the second part the authors show that there is a model of \(\mathrm{I}\Delta_0+\Omega_1+\lnot \mathrm{exp}\) in which \(\Sigma_1\) definable elements are cofinal and for which there is a \(\Sigma_2\) truth definitions and \(\Pi_2\) truth definition for \(\Sigma_1\) sentences and for all \(n\geq 2\) there is a \(\Sigma_n\) truth definition for \(\Sigma_n\) sentences. The last section presents a proof of an older, but previously unpublished result, that the assuption ``Lessan's bound for truth definitions is optimal'' implies that \(\mathrm{I}\Delta_0+\lnot \mathrm{exp}+\lnot \mathrm{B}\Sigma_1\) is consistent. The paper concludes with some comments on why the problem of consistency of \(\mathrm{I}\Delta_0+\lnot \mathrm{exp}+\lnot \mathrm{B}\Sigma_1\) is so hard.
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