Singular spectrum of the Friedrichs model operators in a neighborhood of the singular point (Q679520)
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scientific article; zbMATH DE number 1002993
| Language | Label | Description | Also known as |
|---|---|---|---|
| English | Singular spectrum of the Friedrichs model operators in a neighborhood of the singular point |
scientific article; zbMATH DE number 1002993 |
Statements
Singular spectrum of the Friedrichs model operators in a neighborhood of the singular point (English)
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19 January 1999
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The author considers the selfadjoint operator \[ ({\mathcal L}u)(t)= t^2u(t)+ \int_{\mathbb{R}} v(t,x)u(x)dx\quad\text{for }u\in L^2(\mathbb{R}), \] where the kernel function \(v(.,.)\) is nonnegative and satisfies the smoothness condition \[ \bigl| v(t+h, t+h)+ v(t,t)- v(t+h,t)- v(t,t+ h)\bigr|\leq \omega^2(| h|) \] for \(| h|\leq 1\) with \(\omega\) satisfying \(\omega(t)\downarrow 0\) as \(t\downarrow 0\) and \(\int^1_0(\omega(t)/t) dt< \infty\). The integral operator \(V\) with kernel \(v(.,.)\) is assumed to be of trace class. Under the assumption that either \(\omega(t)= O(t^{{1\over 2}})\) as \(t\to 0\) and \(\text{rank }V< \infty\) or \(\omega(t)= Ct^{{1\over 2}}\) with \(C\leq 1/(\ln 4)^{{1\over 2}}\), he claims that the singular spectrum of \({\mathcal L}\) consists of finitely many eigenvalues of finite multiplicity. On the other hand, if \(\omega(t)= (2/(\ln 4)^{{1\over 2}}) t^{{1\over 2}}\) and \(\text{rank }V= \infty\), then zero is an accumulation point of the eigenvalues of \({\mathcal L}\). More detailed information on the convergence rate of the eigenvalues is also obtained when \(V\) is a certain rank-one operator. No proof is given for the results announced here.
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Friedrichs model
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selfadjoint operator
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integral operator
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trace class
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singular spectrum
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convergence rate of the eigenvalues
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rank-one operators
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