Can one factor the classical adjoint of a generic matrix? (Q862257)
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| English | Can one factor the classical adjoint of a generic matrix? |
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Can one factor the classical adjoint of a generic matrix? (English)
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24 January 2007
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Let \(k\) be an integral domain of characteristic \(0\) and \(n\) be a positive integer. Let \(X\) be a generic \(n\times n\) matrix over \(k\) and \(\text{adj}(X)\) its classical adjoint. The author shows, if \(n\) is odd, then there is no factorization \(\text{adj}(X)=YZ\) into noninvertible matrices. If \(n\) is even and such a factorization exists, then \(\det(Y)=\det(X)^d\) and \(\det(Z)=\det(X)^{n-1-d}\), where \(0<d<n-1\) and \(d=1\) or \(d=n-2\). Further, only one special sort of factorization occurs.
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classical adjoint
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generic matrix
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integral domain
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matrix factorization
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determinant
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