On the recursive sequence \(x_{n+1} = \alpha + \frac{x_{n-1}}{x_n^k}\)

DOI10.1016/j.aml.2008.02.010zbMath1163.39302OpenAlexW2580484860MaRDI QIDQ1027473

Alaa E. Hamza, Ahmed Morsy

Publication date: 29 June 2009

Published in: Applied Mathematics Letters (Search for Journal in Brave)

Full work available at URL: https://doi.org/10.1016/j.aml.2008.02.010

zbMATH Keywords

oscillationboundednessglobal asymptotic stabilitysemicyclesrecursive sequencesperiod 2 solutions

Mathematics Subject Classification ID

Related Items

The difference equation \(x_{n+1}=\alpha + \frac {x_{n-k}}{\Sigma_{i=0}^{k-1} c_{i}x_{n-i}}\) has solutions converging to zero ⋮ On the Difference equation xn+1=axn−l+bxn−k+cxn−sdxn−s−e ⋮ Dynamics of Discrete Operator Equations ⋮ Some discussions on the difference equation \(x_{n + 1} = \alpha +(x_{n - 1}^m / x_n^k)\) ⋮ New method to obtain periodic solutions of period two and three of a rational difference equation ⋮ Quantitative bounds for positive solutions of a Stević difference equation ⋮ Some notes on the difference equation \(x_{n+1} = \alpha + (x_{n-1}/x^k_n)\) ⋮ On the difference equation \(x_{n+1}=\alpha +x_{n - m}/x_{n}^{k}\) ⋮ On the recursive sequence \(x_{n+1}=A+(x_{n - 1}^p/x_n^q)\)

Cites Work

• On the recursive sequence \(x_{n+1}=\alpha+x_{n-1}/x_n\)
• On the recursive sequence \(y_{n+1}=(p+y_{n-1})/(qy_n+y_{n-1})\)
• On the Behavior of Solutions ofx_n+1=p+(x_n−1/x_n)
• Unnamed Item
• Unnamed Item
• Unnamed Item
• Unnamed Item
• Unnamed Item