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On the equation \((x+1)\dots(x+k)=(y+1)\dots(y+mk)\)

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Publication:1190263
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DOI10.1016/0019-3577(92)90029-KzbMath0757.11011MaRDI QIDQ1190263

N. Saradha, Tarlok N. Shorey

Publication date: 27 September 1992

Published in: Indagationes Mathematicae. New Series (Search for Journal in Brave)


zbMATH Keywords

products of consecutive integersequal productsmultiplicative diophantine equations


Mathematics Subject Classification ID

Higher degree equations; Fermat's equation (11D41) Multiplicative and norm form equations (11D57)


Related Items

On arithmetic progressions of equal lengths with equal products, The equations \((x+1)\dots(x+k)=(y+1)\dots(y+mk)\) with \(m=3,4\), On the equation \(x(x +d) \cdots (x +(k - 1)d) = y(y + d) \cdots (y + (mk - 1)d)\), ESTIMATES FOR THE SOLUTIONS OF CERTAIN DIOPHANTINE EQUATIONS BY RUNGE'S METHOD, The equations \((x+1) \cdots (x+k) = (y+1) \cdots (y+m),\quad m=5,6\), On the equation \(f(x+1)\dots f(x+k)= f(y+1)\dots f(y+mk)\), On the equation \(x(x+d_ 1)\dots (x+(k-1)d_ 1)= y(y+d_ 2)\dots (y+(mk-1)d_ 2)\)



Cites Work

  • On the ratio of two blocks of consecutive integers
  • The equations \((x+1)\dots(x+k)=(y+1)\dots(y+mk)\) with \(m=3,4\)
  • On the irreducibility of certain polynomials
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