$A\geqq B\geqq 0$ ensures $(A^{\frac{r}{2}}A^pA^{\frac{r}{2}})^{\frac{1}{q}}\geqq (A^{\frac{r}{2}}B^pA^{\frac{r}{2}})^{\frac{1}{q}}$ for $p\geqq 0$, $q\geqq 1$, $r\geqq 0$ with $(1+r)q\geqq p+r$ and its applications

Related Items (1)

Recommendations

Title not available (Why is that?) 👍 👎
Title not available (Why is that?) 👍 👎
Title not available (Why is that?) 👍 👎
Two inequalities for $_{r}\varphi _{r}$ and applications 👍 👎
A$\geq B\geq 0$ iff $(B^ rA^ pB^ r)^{1/q}\geq B^{(p+2r)/q}$ for r$\geq 0$, p$\geq 0$, q$\geq 1$ with $(1+2r)q\geq p+2r$ 👍 👎
Relations between two inequalities $(B^{\frac r2} A^p B^{\frac r2})^{\frac r{p+r}}\geq B^r$ and $A^p\geq(A^{\frac p2} B^r A^{\frac p2})^{\frac p{p+r}}$ and their applications 👍 👎
$A\geq B\geq 0$ ensures $(B^{\frac r2}A^pB^{\frac r2})^{\frac 1q}\geq(B^{\frac r2}B^pB^{\frac r2})^{\frac 1q}$ for $r\geq 0$, $p\geq 0$, $q\geq 1$ with $(1+r)q\geq p+r$ and its recent applications 👍 👎
A ≧B ≧0 Ensures (BA 2 B) 1/2 ≧B 2 -Solution to a Conjecture on Operator Inequalities 👍 👎
An inequality for r+1_Φ_r and its applications 👍 👎
$A \geq B \geq 0$ Assures $(B^r A^p B^r)^{1/q} \geq B^{(p+2r)/q$ for $r \geq 0$, $p \geq 0$, $q \geq 1$ with $(1 + 2r)q \geq p + 2r$ 👍 👎

This page was built for publication: $A\geqq B\geqq 0$ ensures $(A^{\frac{r}{2}}A^pA^{\frac{r}{2}})^{\frac{1}{q}}\geqq (A^{\frac{r}{2}}B^pA^{\frac{r}{2}})^{\frac{1}{q}}$ for $p\geqq 0$, $q\geqq 1$, $r\geqq 0$ with $(1+r)q\geqq p+r$ and its applications

Report a bug (only for logged in users!)Click here to report a bug for this page (MaRDI item Q2747297)

\(A\geqq B\geqq 0\) ensures \((A^{\frac{r}{2}}A^pA^{\frac{r}{2}})^{\frac{1}{q}}\geqq (A^{\frac{r}{2}}B^pA^{\frac{r}{2}})^{\frac{1}{q}}\) for \(p\geqq 0\), \(q\geqq 1\), \(r\geqq 0\) with \((1+r)q\geqq p+r\) and its applications