A naive proof that \(F_{5n} \equiv 0 \pmod 5\)
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Publication:2868804
zbMATH Open1350.11023MaRDI QIDQ2868804
Publication date: 19 December 2013
Published in: The Fibonacci Quarterly (Search for Journal in Brave)
Full work available at URL: http://fq.math.ca/Abstracts/51-3/hirschhorn2.pdf
Related Items (3)
Title not available (Why is that?) ⋮ Another elementary proof that \(p(11n+6)\equiv 0\pmod{11}\) ⋮ Another proof for the simplicity of \(A_n\) (\(n\geq 5\))
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