The equations \((x+1)\dots(x+k)=(y+1)\dots(y+mk)\) with \(m=3,4\)
In the first article [for the second one, see ibid. 3, No. 1, 79-90 (1992; reviewed below)] the authors show that there are no solutions of the equation \[ (x+1)\dots (x+k)=(y+1)\dots (y+mk) \] for \(m=3\) and \(m=4\) with integers \(x,y\geq 0\), \(k\geq 2\). Extensive use is made of the symbolic computation program MATHEMATICA. In an appendix, Ph. Glesser gives some results, using the algebraic programming languge REDUCE.
scientific article; zbMATH DE number 60871