A remark on the Aleksandrov diameters of finite-dimensional sets
Let L be a linear space, X, Y, Z three norms on L. If BX and BY stand for the unit balls of the normed spaces (L,X) and (L,Y) then the k- dimensional Alexandrov diameters satisfy the inequality \[ a_{k_ 1+k_ 2}(BX,Z)\leq a_{k_ 1}(BX,Y)a_{k_ 2}(BY,Z). \]
scientific article; zbMATH DE number 4163518