Pages that link to "Item:Q1322357"

The following pages link to On the equation \(x(x+d_ 1)\dots (x+(k-1)d_ 1)= y(y+d_ 2)\dots (y+(mk-1)d_ 2)\) (Q1322357):

Displaying 8 items.

• On the equation \((x+1)\dots(x+k)=(y+1)\dots(y+mk)\) (Q1190263) (← links)
• The equations \((x+1)\dots(x+k)=(y+1)\dots(y+mk)\) with \(m=3,4\) (Q1192456) (← links)
• On the equation \(x(x +d) \cdots (x +(k - 1)d) = y(y + d) \cdots (y + (mk - 1)d)\) (Q1196267) (← links)
• On the equation \(f(x+1)\dots f(x+k)= f(y+1)\dots f(y+mk)\) (Q1315091) (← links)
• Polynomial values of figurate numbers (Q2187121) (← links)
• Equation $$x^iy^jx^k=u^iv^ju^k$$ in Words (Q2799193) (← links)
• ON THE EQUATION x(x+d)…(x+(k-1)d)=by 2 (Q4493393) (← links)
• On values of a polynomial at arithmetic progressions with equal products (Q4855238) (← links)